Class 19-20
What are the major issues associated with wind power?
Wind direction is the direction the wind is coming
from
Wind speed typically measured at a height of 10 m
Bg | v (m/s) | v (mph) | Designation | Effect |
---|---|---|---|---|
0 | 0–0.2 | 0-0.45 | No wind | Smoke rises straight up |
1 | 0.3–1.5 | 0.67-3.4 | Light air | Wind direction only detectable from smoke |
2 | 1.6–3.3 | 3.6-7.4 | Light breeze | Palpable wind, leaves rustle |
3 | 3.4–5.4 | 7.6-12 | Gentle breeze | Leaves and thin twigs move |
4 | 5.5–7.9 | 12.3-17.7 | Moderate breeze | Wind moves twigs and thin branches, carries dust |
5 | 8.0–10.7 | 17.9-24 | Fresh breeze | Small trees begin to sway |
6 | 10.8–13.8 | 24.2-30.9 | Strong breeze | Thick branches move, wind begins to whistle |
7 | 13.9–17.1 | 31.1-38.2 | Near gale | Trees in motion, hard to walk |
8 | 17.2–20.7 | 38.5-46,3 | Fresh gale | Twigs broken off trees |
9 | 20.8–24.4 | 46.5-54.6 | Strong gale | Minor damage to buildings and roofs |
10 | 24.5–28.4 | 54.8-63.5 | Whole gale | Trees uprooted |
11 | 28.5–32.6 | 63.7-72.9 | Violent storm | Heavy damage |
12 | ≥ 32.7 | ≥ 73.1 | Hurricane force | Severe damage |
Capacity
Generation
1400 TWh/yr = 160 GW
3 CMO for typical wind farm area
\(A\) = circular area swept by the rotor
Momentum balance: 1 \(\leftrightarrow\) 4 \[\cancel{\dot{\text{accum}}} = \dot{\text{in}} + \dot{\text{out}} + \dot{\text{gen}}\] \[0 = \dot{m}v_1 - \dot{m}v_4 - F\]
Momentum balance: 2 \(\leftrightarrow\) 3 \[0 = \cancelto{\,0,\,v_2=v_3}{\dot{m}v_2 - \dot{m}v_3} +P_2A-P_3A - F\]
Combine these: \[\dot{m}(v_1-v_4) = A(P_2-P_3) = F\]
\(A\) = circular area swept by the rotor
Again: \(\dot{m}(v_1-v_4) = A(P_2-P_3) = F\)
Write \(P_2\) in terms of \(P_1\) using Bernoulli Eq. \[\frac{P_2}{\rho} + \frac{v_2^2}{2} = \frac{P_1}{\rho} + \frac{v_1^2}{2}\] \[P_2 = P_1 + \frac{\rho v_1^2}{2} - \frac{\rho v_2^2}{2}\]
Similarly for \(P_3\) in terms of \(P_4\) \[P_3 = P_4 + \frac{\rho v_4^2}{2} - \frac{\rho v_3^2}{2}\]
Now, insert these into \(\dot{m}(v_1-v_4) = A(P_2-P_3)\)
\[\frac{\rho A}{2}(v_1^2 - v_4^2) = \dot{m}(v_1-v_4)\]
Let \(v=v_2=v_3\) with \(\dot{m}=\rho Av\). This gives \[v = \frac{1}{2}(v_1+v_4)\]
Now, power is \(\dot{m}\) times change in KE: \[\dot{W}= \frac{1}{2}\dot{m}(v_1^2 - v_4^2) = \frac{1}{4}\rho A(v_1+v_4)(v_1^2-v_4^2)\]
\[\dot{W}_\text{max} = \frac{8}{27}\rho Av_1^3\]
The “available” power of the air is \[\dot{W}_\text{avail} = \frac{1}{2}\dot{m}v_1^2 = \frac{1}{2}\rho Av_1^3\]
\[C_p = \frac{\dot{W}}{\dot{W}_\text{avail}}\]\[C_{p,\text{max}} = \frac{16}{27} = 0.5926 \text{ is the Betz number}\] \[\eta = \frac{C_p}{C_{p,\text{max}}}\]
\(\omega R/V = \lambda\) is common
notation
See also: link.
San Gorgonio Pass, CA
Wake turbulence behind individual wind turbines can be seen in the fog in this aerial photo of the Horns Rev wind farm off the Western coast of Denmark. Data collected from wind farms such as this one provide validation to simulation models.